6(2y+1)=36

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Solution for 6(2y+1)=36 equation: 



6(2y+1)=36

We move all terms to the left:

6(2y+1)-(36)=0

We multiply parentheses

12y+6-36=0

We add all the numbers together, and all the variables

12y-30=0

We move all terms containing y to the left, all other terms to the right

12y=30

y=30/12

y=2+1/2

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