6(2y+2)=2(5y+7)

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Solution for 6(2y+2)=2(5y+7) equation: 



6(2y+2)=2(5y+7)

We move all terms to the left:

6(2y+2)-(2(5y+7))=0

We multiply parentheses

12y-(2(5y+7))+12=0



We calculate terms in parentheses: -(2(5y+7)), so:

2(5y+7)

We multiply parentheses

10y+14

Back to the equation:

-(10y+14)



We get rid of parentheses

12y-10y-14+12=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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