6(2y+3)-(5y-44)=4(4y+2)

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Solution for 6(2y+3)-(5y-44)=4(4y+2) equation: 



6(2y+3)-(5y-44)=4(4y+2)

We move all terms to the left:

6(2y+3)-(5y-44)-(4(4y+2))=0

We multiply parentheses

12y-(5y-44)-(4(4y+2))+18=0

We get rid of parentheses

12y-5y-(4(4y+2))+44+18=0



We calculate terms in parentheses: -(4(4y+2)), so:

4(4y+2)

We multiply parentheses

16y+8

Back to the equation:

-(16y+8)



We add all the numbers together, and all the variables

7y-(16y+8)+62=0

We get rid of parentheses

7y-16y-8+62=0

We add all the numbers together, and all the variables

-9y+54=0

We move all terms containing y to the left, all other terms to the right

-9y=-54

y=-54/-9

y=+6

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