6(2y+3)=-1y+7

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Solution for 6(2y+3)=-1y+7 equation: 



6(2y+3)=-1y+7

We move all terms to the left:

6(2y+3)-(-1y+7)=0

We multiply parentheses

12y-(-1y+7)+18=0

We get rid of parentheses

12y+1y-7+18=0

We add all the numbers together, and all the variables

13y+11=0

We move all terms containing y to the left, all other terms to the right

13y=-11

y=-11/13

y=-11/13

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