6(2y+3)=17y-7

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Solution for 6(2y+3)=17y-7 equation: 



6(2y+3)=17y-7

We move all terms to the left:

6(2y+3)-(17y-7)=0

We multiply parentheses

12y-(17y-7)+18=0

We get rid of parentheses

12y-17y+7+18=0

We add all the numbers together, and all the variables

-5y+25=0

We move all terms containing y to the left, all other terms to the right

-5y=-25

y=-25/-5

y=+5

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