6(2y+3)=3(2y+18)

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Solution for 6(2y+3)=3(2y+18) equation:



6(2y+3)=3(2y+18)
We move all terms to the left:
6(2y+3)-(3(2y+18))=0
We multiply parentheses
12y-(3(2y+18))+18=0
We calculate terms in parentheses: -(3(2y+18)), so:
3(2y+18)
We multiply parentheses
6y+54
Back to the equation:
-(6y+54)
We get rid of parentheses
12y-6y-54+18=0
We add all the numbers together, and all the variables
6y-36=0
We move all terms containing y to the left, all other terms to the right
6y=36
y=36/6
y=6

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