6(2y+3)=3(2y+18)

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Solution for 6(2y+3)=3(2y+18) equation: 



6(2y+3)=3(2y+18)

We move all terms to the left:

6(2y+3)-(3(2y+18))=0

We multiply parentheses

12y-(3(2y+18))+18=0



We calculate terms in parentheses: -(3(2y+18)), so:

3(2y+18)

We multiply parentheses

6y+54

Back to the equation:

-(6y+54)



We get rid of parentheses

12y-6y-54+18=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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