6(2y+3)=6

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Solution for 6(2y+3)=6 equation: 



6(2y+3)=6

We move all terms to the left:

6(2y+3)-(6)=0

We multiply parentheses

12y+18-6=0

We add all the numbers together, and all the variables

12y+12=0

We move all terms containing y to the left, all other terms to the right

12y=-12

y=-12/12

y=-1

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