6(2y+4)-15=2(5y-5)-5

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Solution for 6(2y+4)-15=2(5y-5)-5 equation: 



6(2y+4)-15=2(5y-5)-5

We move all terms to the left:

6(2y+4)-15-(2(5y-5)-5)=0

We multiply parentheses

12y-(2(5y-5)-5)+24-15=0



We calculate terms in parentheses: -(2(5y-5)-5), so:

2(5y-5)-5

We multiply parentheses

10y-10-5

We add all the numbers together, and all the variables

10y-15

Back to the equation:

-(10y-15)



We add all the numbers together, and all the variables

12y-(10y-15)+9=0

We get rid of parentheses

12y-10y+15+9=0

We add all the numbers together, and all the variables

2y+24=0

We move all terms containing y to the left, all other terms to the right

2y=-24

y=-24/2

y=-12

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