6(2y+5)=12y+30

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Solution for 6(2y+5)=12y+30 equation: 



6(2y+5)=12y+30

We move all terms to the left:

6(2y+5)-(12y+30)=0

We multiply parentheses

12y-(12y+30)+30=0

We get rid of parentheses

12y-12y-30+30=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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