6(2y+y)=3(3-3y)

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Solution for 6(2y+y)=3(3-3y) equation: 



6(2y+y)=3(3-3y)

We move all terms to the left:

6(2y+y)-(3(3-3y))=0

We add all the numbers together, and all the variables

6(+3y)-(3(-3y+3))=0

We multiply parentheses

18y-(3(-3y+3))=0



We calculate terms in parentheses: -(3(-3y+3)), so:

3(-3y+3)

We multiply parentheses

-9y+9

Back to the equation:

-(-9y+9)



We get rid of parentheses

18y+9y-9=0

We add all the numbers together, and all the variables

27y-9=0

We move all terms containing y to the left, all other terms to the right

27y=9

y=9/27

y=1/3

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