6(2y-1)+4y=5(y+3)+6y+4

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Solution for 6(2y-1)+4y=5(y+3)+6y+4 equation: 



6(2y-1)+4y=5(y+3)+6y+4

We move all terms to the left:

6(2y-1)+4y-(5(y+3)+6y+4)=0

We add all the numbers together, and all the variables

4y+6(2y-1)-(5(y+3)+6y+4)=0

We multiply parentheses

4y+12y-(5(y+3)+6y+4)-6=0



We calculate terms in parentheses: -(5(y+3)+6y+4), so:

5(y+3)+6y+4

We add all the numbers together, and all the variables

6y+5(y+3)+4

We multiply parentheses

6y+5y+15+4

We add all the numbers together, and all the variables

11y+19

Back to the equation:

-(11y+19)



We add all the numbers together, and all the variables

16y-(11y+19)-6=0

We get rid of parentheses

16y-11y-19-6=0

We add all the numbers together, and all the variables

5y-25=0

We move all terms containing y to the left, all other terms to the right

5y=25

y=25/5

y=5

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