6(2y-1)-5(y+1)=0

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Solution for 6(2y-1)-5(y+1)=0 equation: 



6(2y-1)-5(y+1)=0

We multiply parentheses

12y-5y-6-5=0

We add all the numbers together, and all the variables

7y-11=0

We move all terms containing y to the left, all other terms to the right

7y=11

y=11/7

y=1+4/7

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