6(2y-1)=4y-3+3y-8

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Solution for 6(2y-1)=4y-3+3y-8 equation: 



6(2y-1)=4y-3+3y-8

We move all terms to the left:

6(2y-1)-(4y-3+3y-8)=0

We add all the numbers together, and all the variables

6(2y-1)-(7y-11)=0

We multiply parentheses

12y-(7y-11)-6=0

We get rid of parentheses

12y-7y+11-6=0

We add all the numbers together, and all the variables

5y+5=0

We move all terms containing y to the left, all other terms to the right

5y=-5

y=-5/5

y=-1

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