6(2y-10)=72

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Solution for 6(2y-10)=72 equation: 



6(2y-10)=72

We move all terms to the left:

6(2y-10)-(72)=0

We multiply parentheses

12y-60-72=0

We add all the numbers together, and all the variables

12y-132=0

We move all terms containing y to the left, all other terms to the right

12y=132

y=132/12

y=11

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