6(2y-2)=-28

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Solution for 6(2y-2)=-28 equation: 



6(2y-2)=-28

We move all terms to the left:

6(2y-2)-(-28)=0

We add all the numbers together, and all the variables

6(2y-2)+28=0

We multiply parentheses

12y-12+28=0

We add all the numbers together, and all the variables

12y+16=0

We move all terms containing y to the left, all other terms to the right

12y=-16

y=-16/12

y=-1+1/3

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