6(2y-4)-4y=8

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Solution for 6(2y-4)-4y=8 equation: 



6(2y-4)-4y=8

We move all terms to the left:

6(2y-4)-4y-(8)=0

We add all the numbers together, and all the variables

-4y+6(2y-4)-8=0

We multiply parentheses

-4y+12y-24-8=0

We add all the numbers together, and all the variables

8y-32=0

We move all terms containing y to the left, all other terms to the right

8y=32

y=32/8

y=4

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