6(2y-5)=-(y+4)

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Solution for 6(2y-5)=-(y+4) equation: 



6(2y-5)=-(y+4)

We move all terms to the left:

6(2y-5)-(-(y+4))=0

We multiply parentheses

12y-(-(y+4))-30=0



We calculate terms in parentheses: -(-(y+4)), so:

-(y+4)

We get rid of parentheses

-y-4

We add all the numbers together, and all the variables

-1y-4

Back to the equation:

-(-1y-4)



We get rid of parentheses

12y+1y+4-30=0

We add all the numbers together, and all the variables

13y-26=0

We move all terms containing y to the left, all other terms to the right

13y=26

y=26/13

y=2

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