6(2z+2)=11z+2)-43

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Solution for 6(2z+2)=11z+2)-43 equation:



6(2z+2)=11z+2)-43
We move all terms to the left:
6(2z+2)-(11z+2)-43)=0
We add all the numbers together, and all the variables
6(2z+2)-(11z+2)=0
We multiply parentheses
12z-(11z+2)+12=0
We get rid of parentheses
12z-11z-2+12=0
We add all the numbers together, and all the variables
z+10=0
We move all terms containing z to the left, all other terms to the right
z=-10

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