6(2z+3)+3z=22

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Solution for 6(2z+3)+3z=22 equation:


6 (2z+3)+3z=22

We simplify the equation to the form, which is simple to understand 
6(2z+3)+3z=22

Reorder the terms in parentheses
+(+12z+18)+3z=22

Remove unnecessary parentheses
+12z+18+3z=+22

We move all terms containing z to the left and all other terms to the right. 
+12z+3z=+22-18

We simplify left and right side of the equation. 
+15z=+4

We divide both sides of the equation by 15 to get z. 
z=0.266666666667

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