6(2z-1)-2(7+3)=5(z+1)

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Solution for 6(2z-1)-2(7+3)=5(z+1) equation:


Simplifying
6(2z + -1) + -2(7 + 3) = 5(z + 1)

Reorder the terms:
6(-1 + 2z) + -2(7 + 3) = 5(z + 1)
(-1 * 6 + 2z * 6) + -2(7 + 3) = 5(z + 1)
(-6 + 12z) + -2(7 + 3) = 5(z + 1)

Combine like terms: 7 + 3 = 10
-6 + 12z + -2(10) = 5(z + 1)

Multiply -2 * 10
-6 + 12z + -20 = 5(z + 1)

Reorder the terms:
-6 + -20 + 12z = 5(z + 1)

Combine like terms: -6 + -20 = -26
-26 + 12z = 5(z + 1)

Reorder the terms:
-26 + 12z = 5(1 + z)
-26 + 12z = (1 * 5 + z * 5)
-26 + 12z = (5 + 5z)

Solving
-26 + 12z = 5 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-26 + 12z + -5z = 5 + 5z + -5z

Combine like terms: 12z + -5z = 7z
-26 + 7z = 5 + 5z + -5z

Combine like terms: 5z + -5z = 0
-26 + 7z = 5 + 0
-26 + 7z = 5

Add '26' to each side of the equation.
-26 + 26 + 7z = 5 + 26

Combine like terms: -26 + 26 = 0
0 + 7z = 5 + 26
7z = 5 + 26

Combine like terms: 5 + 26 = 31
7z = 31

Divide each side by '7'.
z = 4.428571429

Simplifying
z = 4.428571429

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