6(2z-1)-2(z+3)=3(z+1)

Solution for 6(2z-1)-2(z+3)=3(z+1) equation:

Simplifying
6(2z + -1) + -2(z + 3) = 3(z + 1)

Reorder the terms:
6(-1 + 2z) + -2(z + 3) = 3(z + 1)
(-1 * 6 + 2z * 6) + -2(z + 3) = 3(z + 1)
(-6 + 12z) + -2(z + 3) = 3(z + 1)

Reorder the terms:
-6 + 12z + -2(3 + z) = 3(z + 1)
-6 + 12z + (3 * -2 + z * -2) = 3(z + 1)
-6 + 12z + (-6 + -2z) = 3(z + 1)

Reorder the terms:
-6 + -6 + 12z + -2z = 3(z + 1)

Combine like terms: -6 + -6 = -12
-12 + 12z + -2z = 3(z + 1)

Combine like terms: 12z + -2z = 10z
-12 + 10z = 3(z + 1)

Reorder the terms:
-12 + 10z = 3(1 + z)
-12 + 10z = (1 * 3 + z * 3)
-12 + 10z = (3 + 3z)

Solving
-12 + 10z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-12 + 10z + -3z = 3 + 3z + -3z

Combine like terms: 10z + -3z = 7z
-12 + 7z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-12 + 7z = 3 + 0
-12 + 7z = 3

Add '12' to each side of the equation.
-12 + 12 + 7z = 3 + 12

Combine like terms: -12 + 12 = 0
0 + 7z = 3 + 12
7z = 3 + 12

Combine like terms: 3 + 12 = 15
7z = 15

Divide each side by '7'.
z = 2.142857143

Simplifying
z = 2.142857143