6(2z-1)-2(z+4)=5(z+1)

Solution for 6(2z-1)-2(z+4)=5(z+1) equation:

Simplifying
6(2z + -1) + -2(z + 4) = 5(z + 1)

Reorder the terms:
6(-1 + 2z) + -2(z + 4) = 5(z + 1)
(-1 * 6 + 2z * 6) + -2(z + 4) = 5(z + 1)
(-6 + 12z) + -2(z + 4) = 5(z + 1)

Reorder the terms:
-6 + 12z + -2(4 + z) = 5(z + 1)
-6 + 12z + (4 * -2 + z * -2) = 5(z + 1)
-6 + 12z + (-8 + -2z) = 5(z + 1)

Reorder the terms:
-6 + -8 + 12z + -2z = 5(z + 1)

Combine like terms: -6 + -8 = -14
-14 + 12z + -2z = 5(z + 1)

Combine like terms: 12z + -2z = 10z
-14 + 10z = 5(z + 1)

Reorder the terms:
-14 + 10z = 5(1 + z)
-14 + 10z = (1 * 5 + z * 5)
-14 + 10z = (5 + 5z)

Solving
-14 + 10z = 5 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-14 + 10z + -5z = 5 + 5z + -5z

Combine like terms: 10z + -5z = 5z
-14 + 5z = 5 + 5z + -5z

Combine like terms: 5z + -5z = 0
-14 + 5z = 5 + 0
-14 + 5z = 5

Add '14' to each side of the equation.
-14 + 14 + 5z = 5 + 14

Combine like terms: -14 + 14 = 0
0 + 5z = 5 + 14
5z = 5 + 14

Combine like terms: 5 + 14 = 19
5z = 19

Divide each side by '5'.
z = 3.8

Simplifying
z = 3.8