6(2z-1)-3(z+2)=5(z+1)

Solution for 6(2z-1)-3(z+2)=5(z+1) equation:

Simplifying
6(2z + -1) + -3(z + 2) = 5(z + 1)

Reorder the terms:
6(-1 + 2z) + -3(z + 2) = 5(z + 1)
(-1 * 6 + 2z * 6) + -3(z + 2) = 5(z + 1)
(-6 + 12z) + -3(z + 2) = 5(z + 1)

Reorder the terms:
-6 + 12z + -3(2 + z) = 5(z + 1)
-6 + 12z + (2 * -3 + z * -3) = 5(z + 1)
-6 + 12z + (-6 + -3z) = 5(z + 1)

Reorder the terms:
-6 + -6 + 12z + -3z = 5(z + 1)

Combine like terms: -6 + -6 = -12
-12 + 12z + -3z = 5(z + 1)

Combine like terms: 12z + -3z = 9z
-12 + 9z = 5(z + 1)

Reorder the terms:
-12 + 9z = 5(1 + z)
-12 + 9z = (1 * 5 + z * 5)
-12 + 9z = (5 + 5z)

Solving
-12 + 9z = 5 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-12 + 9z + -5z = 5 + 5z + -5z

Combine like terms: 9z + -5z = 4z
-12 + 4z = 5 + 5z + -5z

Combine like terms: 5z + -5z = 0
-12 + 4z = 5 + 0
-12 + 4z = 5

Add '12' to each side of the equation.
-12 + 12 + 4z = 5 + 12

Combine like terms: -12 + 12 = 0
0 + 4z = 5 + 12
4z = 5 + 12

Combine like terms: 5 + 12 = 17
4z = 17

Divide each side by '4'.
z = 4.25

Simplifying
z = 4.25