6(2z-1)-3(z+9)=(z+1)

Solution for 6(2z-1)-3(z+9)=(z+1) equation:

Simplifying
6(2z + -1) + -3(z + 9) = (z + 1)

Reorder the terms:
6(-1 + 2z) + -3(z + 9) = (z + 1)
(-1 * 6 + 2z * 6) + -3(z + 9) = (z + 1)
(-6 + 12z) + -3(z + 9) = (z + 1)

Reorder the terms:
-6 + 12z + -3(9 + z) = (z + 1)
-6 + 12z + (9 * -3 + z * -3) = (z + 1)
-6 + 12z + (-27 + -3z) = (z + 1)

Reorder the terms:
-6 + -27 + 12z + -3z = (z + 1)

Combine like terms: -6 + -27 = -33
-33 + 12z + -3z = (z + 1)

Combine like terms: 12z + -3z = 9z
-33 + 9z = (z + 1)

Reorder the terms:
-33 + 9z = (1 + z)

Remove parenthesis around (1 + z)
-33 + 9z = 1 + z

Solving
-33 + 9z = 1 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-33 + 9z + -1z = 1 + z + -1z

Combine like terms: 9z + -1z = 8z
-33 + 8z = 1 + z + -1z

Combine like terms: z + -1z = 0
-33 + 8z = 1 + 0
-33 + 8z = 1

Add '33' to each side of the equation.
-33 + 33 + 8z = 1 + 33

Combine like terms: -33 + 33 = 0
0 + 8z = 1 + 33
8z = 1 + 33

Combine like terms: 1 + 33 = 34
8z = 34

Divide each side by '8'.
z = 4.25

Simplifying
z = 4.25