6(2z-1)-4(z+2)=3(z+1)

Solution for 6(2z-1)-4(z+2)=3(z+1) equation:

Simplifying
6(2z + -1) + -4(z + 2) = 3(z + 1)

Reorder the terms:
6(-1 + 2z) + -4(z + 2) = 3(z + 1)
(-1 * 6 + 2z * 6) + -4(z + 2) = 3(z + 1)
(-6 + 12z) + -4(z + 2) = 3(z + 1)

Reorder the terms:
-6 + 12z + -4(2 + z) = 3(z + 1)
-6 + 12z + (2 * -4 + z * -4) = 3(z + 1)
-6 + 12z + (-8 + -4z) = 3(z + 1)

Reorder the terms:
-6 + -8 + 12z + -4z = 3(z + 1)

Combine like terms: -6 + -8 = -14
-14 + 12z + -4z = 3(z + 1)

Combine like terms: 12z + -4z = 8z
-14 + 8z = 3(z + 1)

Reorder the terms:
-14 + 8z = 3(1 + z)
-14 + 8z = (1 * 3 + z * 3)
-14 + 8z = (3 + 3z)

Solving
-14 + 8z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-14 + 8z + -3z = 3 + 3z + -3z

Combine like terms: 8z + -3z = 5z
-14 + 5z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-14 + 5z = 3 + 0
-14 + 5z = 3

Add '14' to each side of the equation.
-14 + 14 + 5z = 3 + 14

Combine like terms: -14 + 14 = 0
0 + 5z = 3 + 14
5z = 3 + 14

Combine like terms: 3 + 14 = 17
5z = 17

Divide each side by '5'.
z = 3.4

Simplifying
z = 3.4