6(2z-1)-4(z+3)=3(z+1)

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Solution for 6(2z-1)-4(z+3)=3(z+1) equation:


6(2z-1)-4(z+3)=3(z+1)

We simplify the equation to the form, which is simple to understand 
6(2z-1)-4(z+3)=3(z+1)

Reorder the terms in parentheses
+(+12z-6)-4*(z+3)=3*(z+1)

Remove unnecessary parentheses
+12z-6-4+*(+z+3+)=+3+*(+z+1+)

Reorder the terms in parentheses
+12z-6+(-4z-12)=3*(z+1)

Remove unnecessary parentheses
+12z-6-4z-12=+3+*(+z+1+)

Reorder the terms in parentheses
+12z-6-4z-12=+(+3z+3)

Remove unnecessary parentheses
+12z-6-4z-12=+3z+3

We move all terms containing z to the left and all other terms to the right. 
+12z-4z-3z=+3+6+12

We simplify left and right side of the equation. 
+5z=+21

We divide both sides of the equation by 5 to get z. 
z=4.2

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