6(2z-1)-5(z+1)=2(z+1)

Solution for 6(2z-1)-5(z+1)=2(z+1) equation:

Simplifying
6(2z + -1) + -5(z + 1) = 2(z + 1)

Reorder the terms:
6(-1 + 2z) + -5(z + 1) = 2(z + 1)
(-1 * 6 + 2z * 6) + -5(z + 1) = 2(z + 1)
(-6 + 12z) + -5(z + 1) = 2(z + 1)

Reorder the terms:
-6 + 12z + -5(1 + z) = 2(z + 1)
-6 + 12z + (1 * -5 + z * -5) = 2(z + 1)
-6 + 12z + (-5 + -5z) = 2(z + 1)

Reorder the terms:
-6 + -5 + 12z + -5z = 2(z + 1)

Combine like terms: -6 + -5 = -11
-11 + 12z + -5z = 2(z + 1)

Combine like terms: 12z + -5z = 7z
-11 + 7z = 2(z + 1)

Reorder the terms:
-11 + 7z = 2(1 + z)
-11 + 7z = (1 * 2 + z * 2)
-11 + 7z = (2 + 2z)

Solving
-11 + 7z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-11 + 7z + -2z = 2 + 2z + -2z

Combine like terms: 7z + -2z = 5z
-11 + 5z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-11 + 5z = 2 + 0
-11 + 5z = 2

Add '11' to each side of the equation.
-11 + 11 + 5z = 2 + 11

Combine like terms: -11 + 11 = 0
0 + 5z = 2 + 11
5z = 2 + 11

Combine like terms: 2 + 11 = 13
5z = 13

Divide each side by '5'.
z = 2.6

Simplifying
z = 2.6