6(2z-1)-5(z+8)=5(z+1)

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Solution for 6(2z-1)-5(z+8)=5(z+1) equation: 



6(2z-1)-5(z+8)=5(z+1)

We move all terms to the left:

6(2z-1)-5(z+8)-(5(z+1))=0

We multiply parentheses

12z-5z-(5(z+1))-6-40=0



We calculate terms in parentheses: -(5(z+1)), so:

5(z+1)

We multiply parentheses

5z+5

Back to the equation:

-(5z+5)



We add all the numbers together, and all the variables

7z-(5z+5)-46=0

We get rid of parentheses

7z-5z-5-46=0

We add all the numbers together, and all the variables

2z-51=0

We move all terms containing z to the left, all other terms to the right

2z=51

z=51/2

z=25+1/2

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