6(2z-3)+4z+24=70

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Solution for 6(2z-3)+4z+24=70 equation: 



6(2z-3)+4z+24=70

We move all terms to the left:

6(2z-3)+4z+24-(70)=0

We add all the numbers together, and all the variables

4z+6(2z-3)-46=0

We multiply parentheses

4z+12z-18-46=0

We add all the numbers together, and all the variables

16z-64=0

We move all terms containing z to the left, all other terms to the right

16z=64

z=64/16

z=4

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