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6(2z-3)=9(z+5)
We move all terms to the left:
6(2z-3)-(9(z+5))=0
We multiply parentheses
12z-(9(z+5))-18=0
We calculate terms in parentheses: -(9(z+5)), so:We get rid of parentheses
9(z+5)
We multiply parentheses
9z+45
Back to the equation:
-(9z+45)
12z-9z-45-18=0
We add all the numbers together, and all the variables
3z-63=0
We move all terms containing z to the left, all other terms to the right
3z=63
z=63/3
z=21
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