6(2z-9)=-42

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Solution for 6(2z-9)=-42 equation: 



6(2z-9)=-42

We move all terms to the left:

6(2z-9)-(-42)=0

We add all the numbers together, and all the variables

6(2z-9)+42=0

We multiply parentheses

12z-54+42=0

We add all the numbers together, and all the variables

12z-12=0

We move all terms containing z to the left, all other terms to the right

12z=12

z=12/12

z=1

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