6(3+2d)=32

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Solution for 6(3+2d)=32 equation: 



6(3+2d)=32

We move all terms to the left:

6(3+2d)-(32)=0

We add all the numbers together, and all the variables

6(2d+3)-32=0

We multiply parentheses

12d+18-32=0

We add all the numbers together, and all the variables

12d-14=0

We move all terms containing d to the left, all other terms to the right

12d=14

d=14/12

d=1+1/6

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