6(3+3b)=126

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Solution for 6(3+3b)=126 equation: 



6(3+3b)=126

We move all terms to the left:

6(3+3b)-(126)=0

We add all the numbers together, and all the variables

6(3b+3)-126=0

We multiply parentheses

18b+18-126=0

We add all the numbers together, and all the variables

18b-108=0

We move all terms containing b to the left, all other terms to the right

18b=108

b=108/18

b=6

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