6(3+4r)=35+7r

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Solution for 6(3+4r)=35+7r equation: 



6(3+4r)=35+7r

We move all terms to the left:

6(3+4r)-(35+7r)=0

We add all the numbers together, and all the variables

6(4r+3)-(7r+35)=0

We multiply parentheses

24r-(7r+35)+18=0

We get rid of parentheses

24r-7r-35+18=0

We add all the numbers together, and all the variables

17r-17=0

We move all terms containing r to the left, all other terms to the right

17r=17

r=17/17

r=1

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