6(3+7b)+5(2b+4)=18+20b

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Solution for 6(3+7b)+5(2b+4)=18+20b equation:



6(3+7b)+5(2b+4)=18+20b
We move all terms to the left:
6(3+7b)+5(2b+4)-(18+20b)=0
We add all the numbers together, and all the variables
6(7b+3)+5(2b+4)-(20b+18)=0
We multiply parentheses
42b+10b-(20b+18)+18+20=0
We get rid of parentheses
42b+10b-20b-18+18+20=0
We add all the numbers together, and all the variables
32b+20=0
We move all terms containing b to the left, all other terms to the right
32b=-20
b=-20/32
b=-5/8

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