6(3+7b)+5(2b+4)=18+20b

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Solution for 6(3+7b)+5(2b+4)=18+20b equation: 



6(3+7b)+5(2b+4)=18+20b

We move all terms to the left:

6(3+7b)+5(2b+4)-(18+20b)=0

We add all the numbers together, and all the variables

6(7b+3)+5(2b+4)-(20b+18)=0

We multiply parentheses

42b+10b-(20b+18)+18+20=0

We get rid of parentheses

42b+10b-20b-18+18+20=0

We add all the numbers together, and all the variables

32b+20=0

We move all terms containing b to the left, all other terms to the right

32b=-20

b=-20/32

b=-5/8

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