6(3+t)=(2t+5)2

Solution for 6(3+t)=(2t+5)2 equation:

6(3+t)=(2t+5)2

We move all terms to the left:

6(3+t)-((2t+5)2)=0

We add all the numbers together, and all the variables

6(t+3)-((2t+5)2)=0

We multiply parentheses

6t-((2t+5)2)+18=0


We calculate terms in parentheses: -((2t+5)2), so:

(2t+5)2

We multiply parentheses

4t+10

Back to the equation:

-(4t+10)


We get rid of parentheses

6t-4t-10+18=0

We add all the numbers together, and all the variables

2t+8=0

We move all terms containing t to the left, all other terms to the right

2t=-8

t=-8/2

t=-4