6(3+x)+(-20)=10+3(4x+2)

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Solution for 6(3+x)+(-20)=10+3(4x+2) equation: 



6(3+x)+(-20)=10+3(4x+2)

We move all terms to the left:

6(3+x)+(-20)-(10+3(4x+2))=0

We add all the numbers together, and all the variables

6(x+3)-(10+3(4x+2))+(-20)=0

We add all the numbers together, and all the variables

6(x+3)-(10+3(4x+2))-20=0

We multiply parentheses

6x-(10+3(4x+2))+18-20=0



We calculate terms in parentheses: -(10+3(4x+2)), so:

10+3(4x+2)

determiningTheFunctionDomain
3(4x+2)+10

We multiply parentheses

12x+6+10

We add all the numbers together, and all the variables

12x+16

Back to the equation:

-(12x+16)



We add all the numbers together, and all the variables

6x-(12x+16)-2=0

We get rid of parentheses

6x-12x-16-2=0

We add all the numbers together, and all the variables

-6x-18=0

We move all terms containing x to the left, all other terms to the right

-6x=18

x=18/-6

x=-3

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