6(3+x)=2(39+x)

Solution for 6(3+x)=2(39+x) equation:

6(3+x)=2(39+x)

We move all terms to the left:

6(3+x)-(2(39+x))=0

We add all the numbers together, and all the variables

6(x+3)-(2(x+39))=0

We multiply parentheses

6x-(2(x+39))+18=0


We calculate terms in parentheses: -(2(x+39)), so:

2(x+39)

We multiply parentheses

2x+78

Back to the equation:

-(2x+78)


We get rid of parentheses

6x-2x-78+18=0

We add all the numbers together, and all the variables

4x-60=0

We move all terms containing x to the left, all other terms to the right

4x=60

x=60/4

x=15