6(3+x)=8x-99

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Solution for 6(3+x)=8x-99 equation: 



6(3+x)=8x-99

We move all terms to the left:

6(3+x)-(8x-99)=0

We add all the numbers together, and all the variables

6(x+3)-(8x-99)=0

We multiply parentheses

6x-(8x-99)+18=0

We get rid of parentheses

6x-8x+99+18=0

We add all the numbers together, and all the variables

-2x+117=0

We move all terms containing x to the left, all other terms to the right

-2x=-117

x=-117/-2

x=58+1/2

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