6(3+y)-4y=2(3-y)

Solution for 6(3+y)-4y=2(3-y) equation:

6(3+y)-4y=2(3-y)

We move all terms to the left:

6(3+y)-4y-(2(3-y))=0

We add all the numbers together, and all the variables

6(y+3)-4y-(2(-1y+3))=0

We add all the numbers together, and all the variables

-4y+6(y+3)-(2(-1y+3))=0

We multiply parentheses

-4y+6y-(2(-1y+3))+18=0


We calculate terms in parentheses: -(2(-1y+3)), so:

2(-1y+3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)


We add all the numbers together, and all the variables

2y-(-2y+6)+18=0

We get rid of parentheses

2y+2y-6+18=0

We add all the numbers together, and all the variables

4y+12=0

We move all terms containing y to the left, all other terms to the right

4y=-12

y=-12/4

y=-3