6(3-(5+6x))-2x=-14+2(1-19x)

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Solution for 6(3-(5+6x))-2x=-14+2(1-19x) equation: 



6(3-(5+6x))-2x=-14+2(1-19x)

We move all terms to the left:

6(3-(5+6x))-2x-(-14+2(1-19x))=0

We add all the numbers together, and all the variables

6(3-(6x+5))-2x-(-14+2(-19x+1))=0

We add all the numbers together, and all the variables

-2x+6(3-(6x+5))-(-14+2(-19x+1))=0



We calculate terms in parentheses: -(-14+2(-19x+1)), so:

-14+2(-19x+1)

determiningTheFunctionDomain
2(-19x+1)-14

We multiply parentheses

-38x+2-14

We add all the numbers together, and all the variables

-38x-12

Back to the equation:

-(-38x-12)



We get rid of parentheses

-2x+6(3-(6x+5))+38x+12=0

We add all the numbers together, and all the variables

36x+6(3-(6x+5))+12=0

We move all terms containing x to the left, all other terms to the right

36x+6(3-(6x+5))=-12

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