6(3-2x)+4x=10

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Solution for 6(3-2x)+4x=10 equation: 



6(3-2x)+4x=10

We move all terms to the left:

6(3-2x)+4x-(10)=0

We add all the numbers together, and all the variables

6(-2x+3)+4x-10=0

We add all the numbers together, and all the variables

4x+6(-2x+3)-10=0

We multiply parentheses

4x-12x+18-10=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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