6(3-2x)-12=4(5x-4)

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Solution for 6(3-2x)-12=4(5x-4) equation: 



6(3-2x)-12=4(5x-4)

We move all terms to the left:

6(3-2x)-12-(4(5x-4))=0

We add all the numbers together, and all the variables

6(-2x+3)-(4(5x-4))-12=0

We multiply parentheses

-12x-(4(5x-4))+18-12=0



We calculate terms in parentheses: -(4(5x-4)), so:

4(5x-4)

We multiply parentheses

20x-16

Back to the equation:

-(20x-16)



We add all the numbers together, and all the variables

-12x-(20x-16)+6=0

We get rid of parentheses

-12x-20x+16+6=0

We add all the numbers together, and all the variables

-32x+22=0

We move all terms containing x to the left, all other terms to the right

-32x=-22

x=-22/-32

x=11/16

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