6(3-2x)-3x=x+18

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Solution for 6(3-2x)-3x=x+18 equation: 



6(3-2x)-3x=x+18

We move all terms to the left:

6(3-2x)-3x-(x+18)=0

We add all the numbers together, and all the variables

6(-2x+3)-3x-(x+18)=0

We add all the numbers together, and all the variables

-3x+6(-2x+3)-(x+18)=0

We multiply parentheses

-3x-12x-(x+18)+18=0

We get rid of parentheses

-3x-12x-x-18+18=0

We add all the numbers together, and all the variables

-16x=0

x=0/-16

x=0

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