6(3-2x)-4(2x-3)=10(3-2x)

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Solution for 6(3-2x)-4(2x-3)=10(3-2x) equation: 



6(3-2x)-4(2x-3)=10(3-2x)

We move all terms to the left:

6(3-2x)-4(2x-3)-(10(3-2x))=0

We add all the numbers together, and all the variables

6(-2x+3)-4(2x-3)-(10(-2x+3))=0

We multiply parentheses

-12x-8x-(10(-2x+3))+18+12=0



We calculate terms in parentheses: -(10(-2x+3)), so:

10(-2x+3)

We multiply parentheses

-20x+30

Back to the equation:

-(-20x+30)



We add all the numbers together, and all the variables

-20x-(-20x+30)+30=0

We get rid of parentheses

-20x+20x-30+30=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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