6(3-2x)=64

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Solution for 6(3-2x)=64 equation: 



6(3-2x)=64

We move all terms to the left:

6(3-2x)-(64)=0

We add all the numbers together, and all the variables

6(-2x+3)-64=0

We multiply parentheses

-12x+18-64=0

We add all the numbers together, and all the variables

-12x-46=0

We move all terms containing x to the left, all other terms to the right

-12x=46

x=46/-12

x=-3+5/6

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