6(3-3k)+3k=6(-2-5k)

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Solution for 6(3-3k)+3k=6(-2-5k) equation: 



6(3-3k)+3k=6(-2-5k)

We move all terms to the left:

6(3-3k)+3k-(6(-2-5k))=0

We add all the numbers together, and all the variables

6(-3k+3)+3k-(6(-5k-2))=0

We add all the numbers together, and all the variables

3k+6(-3k+3)-(6(-5k-2))=0

We multiply parentheses

3k-18k-(6(-5k-2))+18=0



We calculate terms in parentheses: -(6(-5k-2)), so:

6(-5k-2)

We multiply parentheses

-30k-12

Back to the equation:

-(-30k-12)



We add all the numbers together, and all the variables

-15k-(-30k-12)+18=0

We get rid of parentheses

-15k+30k+12+18=0

We add all the numbers together, and all the variables

15k+30=0

We move all terms containing k to the left, all other terms to the right

15k=-30

k=-30/15

k=-2

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