6(3-b)=2-4(7b+8)

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Solution for 6(3-b)=2-4(7b+8) equation:



6(3-b)=2-4(7b+8)
We move all terms to the left:
6(3-b)-(2-4(7b+8))=0
We add all the numbers together, and all the variables
6(-1b+3)-(2-4(7b+8))=0
We multiply parentheses
-6b-(2-4(7b+8))+18=0
We calculate terms in parentheses: -(2-4(7b+8)), so:
2-4(7b+8)
determiningTheFunctionDomain -4(7b+8)+2
We multiply parentheses
-28b-32+2
We add all the numbers together, and all the variables
-28b-30
Back to the equation:
-(-28b-30)
We get rid of parentheses
-6b+28b+30+18=0
We add all the numbers together, and all the variables
22b+48=0
We move all terms containing b to the left, all other terms to the right
22b=-48
b=-48/22
b=-2+2/11

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