6(3-d)+2d=24-10d

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Solution for 6(3-d)+2d=24-10d equation: 



6(3-d)+2d=24-10d

We move all terms to the left:

6(3-d)+2d-(24-10d)=0

We add all the numbers together, and all the variables

6(-1d+3)+2d-(-10d+24)=0

We add all the numbers together, and all the variables

2d+6(-1d+3)-(-10d+24)=0

We multiply parentheses

2d-6d-(-10d+24)+18=0

We get rid of parentheses

2d-6d+10d-24+18=0

We add all the numbers together, and all the variables

6d-6=0

We move all terms containing d to the left, all other terms to the right

6d=6

d=6/6

d=1

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