6(3-k)=-5(2k+1)+8

Solution for 6(3-k)=-5(2k+1)+8 equation:

6(3-k)=-5(2k+1)+8

We move all terms to the left:

6(3-k)-(-5(2k+1)+8)=0

We add all the numbers together, and all the variables

6(-1k+3)-(-5(2k+1)+8)=0

We multiply parentheses

-6k-(-5(2k+1)+8)+18=0


We calculate terms in parentheses: -(-5(2k+1)+8), so:

-5(2k+1)+8

We multiply parentheses

-10k-5+8

We add all the numbers together, and all the variables

-10k+3

Back to the equation:

-(-10k+3)


We get rid of parentheses

-6k+10k-3+18=0

We add all the numbers together, and all the variables

4k+15=0

We move all terms containing k to the left, all other terms to the right

4k=-15

k=-15/4

k=-3+3/4